9.2  Induced Electric Fields

9.2.1  Motional Electromotive Force

We consider conducting material to have a number (essentially infinite) number of electric charge carriers that are free to move (albeit with resistance unless the conductor is a perfect conductor) throughout the material in any way demanded by external electric and magnetic fields. That means we can consider the source of an induced EMF by looking at the direct effects of an external magnetic field on charges in a moving conductor. For example, if we consider a conducting bar of length L moving in a plane perpendicular to a constant magnetic field, we see that the positive and negative electric charges within the bar will separate as shown in figure 9.8.


Figure 9.8: A conducting bar moving in a magnetic field experiences separation of positive and negative charges within the bar. This leads to an induced EMF across the bar.

The positive charges are pushed to the bottom by the velocity cross magnetic field force and the negative charges are pushed in the opposite direction. The charge separation creates an electric field in the downward direction. This electric field builds as the charge separation grows until the force on the charges due to the resulting electric field cancels the force due to motion in the magnetic field. That means that we have, if we assume the charge q to mean positive charge
q| ®
E
 
|
=
q| ®
v
 
× ®
B
 
| Þ
E = e
L
=
vB Þ
einduced
=
vBL
(9.2.1.14)
where the motional EMF, e, is just the average electric field divided by the length of the bar. It is induced by the motion of the bar in the magnetic field. The magnitude of this EMF is equal in magnitude to the product of the velocity, the magnetic field magnitude, and the length of the bar. If we attach this bar to frictionless rails which provide a resistance R as shown in figure 9.9 and provide an external force on the bar to maintain its constant velocity, then the bar is a source of EMF and just like any other EMF source, can drive a current through the circuit.


Figure 9.9: A conducting bar moving on frictionless rails acts as an EMF source for pushing current through the circuit formed by the bar and the rails.

Note that the motional EMF is identical to the induced EMF we calculated through Faraday's Law. In fact, motional EMF is one example of Faraday's Law. It has a number of practical applications.

Problem 1:
An electromagnetic flowmeter can be used to measure flowrate of a conductive fluid when it is important not to interrupt the flow itself (e.g. blood through an artery during heart surgery). Suppose a voltmeter is used to determine the potential difference across a tube of diameter d as shown in figure 9.10 in the presence of a magnetic field. What is the velocity magnitude, v, if the voltmeter registers 6.12 mV for B = 0.120 T and d = 1.2 cm?


Figure 9.10: Measuring the velocity of a conductive fluid through a tube of diameter d in the presence of a magnetic field.

Solution:
The motional EMF across the fluid to opposite sides of the tube wall should be
e
=
Bdv Þ
v
=
e
Bd
=
6.12×10-3 volts
(0.120 T)(0.012 m)
v
=
4.25 m/s
(9.2.1.15)

Problem 2:
Reconsider problem 3 of the previous lecture in terms of motional EMF. What is the terminal velocity of the loop?
Solution:
Since all parts of the loop move at the same terminal velocity, vy, at equilibrium, we reconsider figure  9.7 in terms of motion EMF on each part of the loop. First, note that the left and right sides are completely symmetric so any forces produced by currents induced by motional EMF must cancel. For the top and bottom parts of the loop, we consider each as an independent EMF source to find
etop
=
| ®
v
 
× ®
B
 
|·l = vy(B0ytop)l
ebot
=
| ®
v
 
× ®
B
 
|·l = vy(B0ybot)l
(9.2.1.16)
Note that the direction of the EMF in both the top and bottom pieces of the loop point to the right. Hence the bottom EMF pushes current counter-clockwise about the loop and the top EMF pushes current clockwise as shown in figure 9.11.


Figure 9.11: The motional EMF on each of the four sides of the conducting loop can be calculated. The net EMF pushes current counter-clockwise around the loop.

The net EMF for the circuit is therefore
enet = ebot - etop = B0lvy(ybot - ytop) = B0lwvy
(9.2.1.17)
if we arbitrarily assign counter-clockwise as the positive direction. The induced current in the loop is
Iinduced = enet
R
= B0lwvy
R
(9.2.1.18)
We see that this is the same as the current we derived in the solution to problem 3 so the conclusion as to the net force acting on the loop and the terminal velocity of the loop is the same.


9.2.2  Induced Electric Fields

In general, since the force on charge carriers in a conductor is given by
®
F
 
= q ®
v
 
× ®
B
 
(9.2.2.19)
we can calculate the motional EMF for a conductor moving in a magnetic field via the following formulation.
®
F
 
= q ®
E
 
=
q ®
v
 
× ®
B
 
Þ
e
=
ó
(ç)
õ

®
E
 
·d ®
l
 
= ó
(ç)
õ

( ®
v
 
× ®
B
 
)·d ®
l
 
Þ
e
=
ó
(ç)
õ

( ®
v
 
× ®
B
 
)·d ®
l
 
and
ó
(ç)
õ

®
E
 
·d ®
l
 
=
e = - dFB
dt
(9.2.2.20)
Hence we see that, in general, we can calculate motional EMF's, i.e. the EMF generated in moving conductors through the interaction of the motion and external magnetic field. The second equation shows that Faraday's Law predicts the creation of an induced electric field in the presence of a time-varying magnetic flux. Note that this second equation and the original expression of Faraday's Law are equivalent and always valid. The calculation of motional EMF's is consistent with Faraday's Law only for the case of motion of a conductor in a magnetic field.

Problem 3:
A square conducting plate of width and length d and mass m falls in a constant gravitational field with acceleration g. The plate falls in the presence of a magnetic field B  directed into the page as shown in figure 9.12. Find the induced EMF between points a and b as a function of time assuming the plate starts falling from rest. What electric field exists between these points as a function of time?


Figure 9.12: A conducting square plate falls in the presence of a magnetic field. An induced EMF across the horizontal plate can be calculated as a function of the vertical velocity of the plate.

Solution:
The motion of the plate causes a motional EMF which we calculate as follows.
eab
=
ó
(ç)
õ

( ®
v
 
× ®
B
 
)·d ®
l
 
=
vBd
eab
=
gtBd
(9.2.2.21)
The electric field is strictly speaking only established for equilibrium charge separation, but if we consider charges as instantaneously at rest at time t, then the electric field is
Eab = Bgt
(9.2.2.22)
Note that since there is no circuit, no steady current flows through the plate. If the magnetic field is not uniform, however, there will be eddy currents which circulate throughout the plate.


9.2.3  Ampere-Maxwell Law

James Clerk Maxwell was responsible for setting down our current understanding of the fundamental importance of the equations that make up Gauss's Law, Faraday's Law, and Ampere's Law. In deciding on a suitable description of electrodynamics, he sought to place the mathematical description on the same footing as Newton's Laws of Motions. That he succeeded is testimony to his mathematical skill and great physical insight.

To start, we should review here the form of the laws as we currently describe them.

Gauss's Law for Static Electric Charges (ò)E·dA = q/e0
Gauss's Law for Magnetism (ò)B·dA = 0
Ampere's Law (ò)B·dl = m0Ienc.
Faraday's Law (ò)E·dl = -dFB/dt

where the second equation represents the fact that there are no magnetic charges observed (so far) in the universe, hence there are no point-like sources or sinks of the magnetic field.

We first note the degree of mathematical symmetry present in the equations despite the differences in behavior of electric and magnetic fields. It's also clear that this symmetry between electric and magnetic fields would be perfect except for two obvious asymmetries within the equations themselves. The first is that there are no magnetic charges as there are electric charges (something that has motivated physicists to seek out such charges for decades) and the second is that, electric fields can be created in two ways: either from static electric charges (Gauss's Law) or induced by time-varying magnetic fields (magnetic fluxes to be exact), but there is no corresponding possibility of creating magnetic fields from either static magnetic charges (they have not been found to exist) nor from time-varying electric fields. If we simply assumed that the latter symmetry had to exist, why would it not be apparent in experiments that were done up to the 1800's? In this, we can make a small digression that points out one of the prime means of gaining insights into physics research.

Let us infer that nature is respectful of symmetry mathematically. What would Maxwell's Equations look like completely symmetrically? First, the existence of magnetic charges would change the form of Gauss's Law applied to static charges. We would have
ó
(ç)
õ

®
E
 
·d ®
A
 
=
qE
e0
ó
(ç)
õ

®
B
 
·d ®
A
 
=
m0 qB
(9.2.3.23)
if units are to be kept consistent. What about currents involving electric and magnetic charges? Certainly there would be contributions to both Ampere's Law and Faraday's Law. These contributions, again looking at consistent units, would look as follows:
ó
(ç)
õ

®
B
 
·d ®
l
 
=
m0IE + k dFE
dt
ó
(ç)
õ

®
E
 
·d ®
l
 
=
- dFB
dt
- m0IB
(9.2.3.24)
where the subscripts E and B depict electric or magnetic charges. The k in the revamped Ampere's Law is a placeholder for the correct proportionality constant for this term. We can find the value of this constant in terms of the fundamental constants m0 and e0 purely from dimensional analysis. Since magnetic monopoles do not exist, we deal simply with the additions necessary to consider induced magnetic fields from time-varying electric field fluxes. This would affect only Ampere's Law and the term added would assume that a time-varying electric flux would induce a B field. To make sure that the units are correct, we would want to have Ampere's Law extended as follows:
ó
(ç)
õ

®
B
 
·d ®
l
 
= m0(Ienc. + Idisplacement)
(9.2.3.25)
where we want
Idisplacement µ dFE
dt
(9.2.3.26)
That is, this new term Idisplacement is proportional to the time-rate of change of electric flux. The simplest form of converting electric flux (SI units of N/(C·m2·s)) to current (C/s) is, interestingly enough, multiplication by a constant with the units C2/(N·m2). Note that these are precisely the units of the permittivity constant, e0! Hence, an ansatz, or educated guess would be
Idisplacment = e0 dFE
dt
(9.2.3.27)
This comes directly from dimensional analysis and a "belief" in the need for symmetry among the equations for electricity and magnetism. Note that this ansatz also gives rise to an assumption as to why the effect might be hard to observe. Note that, if the above form is correct, then Ampere's Law is changed to have the form
ó
(ç)
õ

®
B
 
·d ®
l
 
= m0Ienc. + m0e0 dFE
dt
(9.2.3.28)
This means that the time-varying electric flux term is multiplied by two small terms rather than just one. This might make the effect weak enough to be masked by other experimental interferences unless one is very careful. In fact, the form we have derived for Idisplacement, referred to as the displacement current, does exist and can be verified experimentally. It was motivated by Maxwell theoretically not from the symmetry and dimensional analysis argument above, but from the following consideration of a weakness in Ampere's mathematical description of his law. Consider the case of a capacitor connected to conducting lines. If one of the lines carries a current I, then the other line connected to the other plate must also carry such a current due to the electric field of the previous plate.


Figure 9.13: A charging capacitor and the corresponding time-varying electric field between its plates.

If we apply Ampere's Law to a circular disk around the wire, then the magnetic field is expected to be constant in magnitude and to have a direction which follows the boundary. The magnitude of the B field is proportional to the current penetrating the area bound by the path.


Figure 9.14: Magnetic field around a current as it approaches the capacitor.

Unfortunately, the mathematical description of the area bounded by a curve is rather loose. The area shown in figure 9.15 is bounded by the same curve.


Figure 9.15: Magnetic field around the same perimeter which encloses a different area.

Ampere's Law, as stated, is a line integral which can be shown to be equivalent for the two areas and in fact for any area bounded by the same circular curve around the wire in the region outside the capacitor. The unfortunate part, though, is that no current penetrates the second surface and hence the prediction is that the magnetic field should be zero around the boundary. To resolve the obvious inconsistency, Maxwell generalized Ampere's Law to include the displacement current matching just the characteristics we gave on the basis of the dimensional argument above.

To verify the form of the displacement current, note that a parallel-plate capacitor builds charge according to the current impinging on the left plate for our figure. This current is related to the change in electric flux as follows:
dFE
dt
=
d
dt
(EA)
=
dE
dt
A
=
d
dt
æ
ç
è
q
e0A
ö
÷
ø
A
=
dq
dt
1
e0
FE
dt
=
I
e0
(9.2.3.29)
If we multiply this by e0, we see that we get the displacement current as being equal to the current in the wires attached to the plates of the capacitors, hence we expect to get the same value for the magnetic field no matter whether we draw the surface so as to have the current in the wire penetrate the surface or to have the time-varying electric field between the capacitor plates penetrating the surface.

Let's now look at an example with numbers included.

Problem 4:
Find the magnetic field expected for a capacitor with circular plates of diameter 10 cm, distance between the plates of 1 cm, and a current of 1 A going to one of the plates. Evaluate the magnetic field at both 0.5 cm from the central axis of the capacitor and at distance 20 cm from the axis.


Figure 9.16: Magnetic field in the region between the plates of a charging capacitor.

Solution:
Let's assume that the induced magnetic field follows the symmetry of the plate, namely that it is circular and therefore of equal magnitude at every point around a circle of radius r. Then, we can evaluate the electric flux through a ring of radius r1 < R with R = 5 cm.
FE
=
E(pr12)
=
q
e0pR2
pr12
FE
=
q r12
e0R2
(9.2.3.30)
For r2 > R, we note that the electric field extends only to the edge of the capacitor, so
FE
=
E(pR2)
=
q
e0pR2
pR2
FE
=
q
e0
(9.2.3.31)
The time rate of change of the electric flux for these two cases is
dFE
dt
=
I r12e0
R2
   for r1 < R
dFE
dt
=
I
e0
   for r2 > R
(9.2.3.32)
For either case, the integral of B over an Amperian path gives B(2pr). Therefore, we have, from the Ampere-Maxwell formula
Br1 < R
=
m0I
2p
r1
R2
= (4p×10-7 T·m/A)(1 A)
2p
0.005 m
(0.05 m)2
= 4×10-7 T
Br2 < R
=
m0I
2pr2
= (4p×10-7 T·m/A)(1 A)
2p(0.2 m)
= 10-6 T
(9.2.3.33)
Detecting the magnetic field in the region of the capacitor and separating out any influence due to the magnetic field from the wires is difficult. Fortunately, Maxwell was able to verify the correctness of his ansatz through the theoretical discovery of even more remarkable consequences of his revision of Ampere's Law coupled with the other Maxwell equations.



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